Saturday, September 16, 2006

Why Blog?

I just sent off all of the invitations for you (my students) to join this blog. I've incorporated a blog in our course because I believe it will become another important tool on your "path to success." I have learned some strategies from other teachers that will help to get you started, but remember that this is YOUR space and it will only be as resourceful as YOU make it.

You can write about the topics covered in class, you can post a math question that you are struggling with, you can respond to someone else's question when you think that you can help them out, you can explore the links I've added on the right, or you can suggest some links of your own that will help you and your classmates practise the course material. We are a community of learners so have fun... and help one another.


How To Post: (Thanks Ms.Armstrong!)
  1. Go to URL www.blogger.com or click on the "I Power Blogger" icon in the right column of the page.
  2. Type in the user name and password that you provided when you accepted my invitation to blog.
  3. Click on S2 Pre-calculus WKC
  4. Click on 'Create' under the 'Posting' tab.
  5. Type in your title and your post.
  6. PROOF READ your post.
  7. PROOF READ your post again. (Does it make sense? Is everything spelled correctly??)
  8. Click on the orange button that says 'Publish Post'
I look forward to seeing this develop over the semester!

1 Comments:

At 10:00 p.m., Anonymous Anonymous said...

Hey Everyone, here's mine, karen & shanes answer to #6 of that group assn. we did in class today.
a)Given points A(2,3) B(4,5) & C(6,-1), find an equation for the altitude from A to BC (a.k.a. the height)

Step 1: find the slope of BC so that you can get the reciprocal which will give you the perpendicular line, the altitude.
m= y2-y1 m= -1-5 m= -6 m= -3 *Now flip to get -3 1
----- ---- --- the reciprocal* ---- = ---
x2-x1 6-4 2 1 3

Step 2: Use the formula y=mx+b to get an equation for the altitude. Use the coordinates of A(2,3) and the altitude ( 1
--) --->> y=mx+b (plug in the #s) 3= 1 (2)+ b --> 3= 2 + b --> (get B by itself, 9 2
3 --- --- take away 2/3 --- - --- (multiply 3/1 by 3
3 3 from each side) 3 3 to get common
denominators) -->>

7
--- = b SO 1 7
3 y= ---x + ---
3 3


b)Calculate the area of the triangle.
AREA= B(H) AREA= 6(1/3) AREA= 6/3 AREA= 2
----- ------- --- --- AREA= 1
2 2 2 2


Everybody better post theirs, this took me a long time, haha :)
Goodnight!
-Brittany

 

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